std::chrono::duration<Rep,Period>::operator+=, -=, *=, /=, %=
From cppreference.com
(1) | ||
duration& operator+=( const duration& d ); |
(since C++11) (constexpr since C++17) |
|
(2) | ||
duration& operator-=( const duration& d ); |
(since C++11) (constexpr since C++17) |
|
(3) | ||
duration& operator*=( const rep& rhs ); |
(since C++11) (constexpr since C++17) |
|
(4) | ||
duration& operator/=( const rep& rhs ); |
(since C++11) (constexpr since C++17) |
|
(5) | ||
duration& operator%=( const rep& rhs ); |
(since C++11) (constexpr since C++17) |
|
(6) | ||
duration& operator%=( const duration& rhs ); |
(since C++11) (constexpr since C++17) |
|
Performs compound assignments between two durations with the same period or between a duration and a tick count value.
If rep_
is the member variable holding the number of ticks in this duration object,
1) Equivalent to rep_ += d.count(); return *this;.
2) Equivalent to rep_ -= d.count(); return *this;.
3) Equivalent to rep_ *= rhs; return *this;.
4) Equivalent to rep_ /= rhs; return *this;.
5) Equivalent to rep_ %= rhs; return *this;.
6) Equivalent to rep_ %= d.count(); return *this;.
Parameters
d | - | duration on the right-hand side of the operator |
rhs | - | number of ticks on the right-hand side of the operator |
Return value
A reference to this duration after modification.
Example
Run this code
#include <chrono> #include <iostream> int main() { std::chrono::minutes m(11); m *= 2; m += std::chrono::hours(10); // hours implicitly convert to minutes std::cout << m.count() << " minutes equals " << std::chrono::duration_cast<std::chrono::hours>(m).count() << " hours and "; m %= std::chrono::hours(1); std::cout << m.count() << " minutes\n"; }
Output:
622 minutes equals 10 hours and 22 minutes
See also
increments or decrements the tick count (public member function) | |
implements arithmetic operations with durations as arguments (function template) |