std::move_iterator<Iter>::base
From cppreference.com
< cpp | iterator | move iterator
(1) | ||
iterator_type base() const; |
(constexpr since C++17) (until C++20) |
|
constexpr const iterator_type& base() const& noexcept; |
(since C++20) | |
constexpr iterator_type base() &&; |
(2) | (since C++20) |
Returns the underlying iterator.
1) Returns a copy of(until C++20)reference to(since C++20) the underlying iterator.
2) Returns an iterator move constructed from the underlying iterator.
Return value
1)
current
2) std::move(
current
)Example
Run this code
#include <algorithm> #include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> v{0, 1, 2, 3, 4}; std::move_iterator<std::vector<int>::reverse_iterator> m1{v.rbegin()}, m2{v.rend()}; std::copy(m1.base(), m2.base(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Output:
4 3 2 1 0
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3391 | C++20 | overload (1) returned a copy of the underlying iterator | returns a reference |
LWG 3593 | C++20 | overload (1) was not noexcept | made noexcept |
See also
(C++11)(C++11)(deprecated in C++20) |
accesses the pointed-to element (public member function) |