std::indirect_result_t
From cppreference.com
Defined in header <iterator>
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template< class F, class... Is > requires (std::indirectly_readable<Is> && ...) && |
(since C++20) | |
The alias template indirect_result_t
obtains the result type of invoking an invocable
type F
on the result of dereferencing indirectly_readable
types Is...
.
Template parameters
F | - | an invocable type |
Is | - | indirectly readable types that are dereferenced to arguments |
Example
Run this code
#include <iterator> #include <type_traits> struct Fn { long operator()(const int&); int operator()(int&&); short operator()(int, int) const; auto operator()(const float) -> int&; void operator()(int[8]); }; static_assert( std::is_same_v<std::indirect_result_t<Fn, const int*>, long> and std::is_same_v<std::indirect_result_t<Fn, std::move_iterator<int*>>, int> and std::is_same_v<std::indirect_result_t<const Fn, int*, int*>, short> and std::is_same_v<std::indirect_result_t<Fn, float*>, int&> and std::is_same_v<std::indirect_result_t<Fn, int**>, void> ); int main() {}
See also
(C++11)(removed in C++20)(C++17) |
deduces the result type of invoking a callable object with a set of arguments (class template) |
(C++26) |
computes the value type of an indirectly_readable type by projection(alias template) |