operator-(std::reverse_iterator)
From cppreference.com
< cpp | iterator | reverse iterator
Defined in header <iterator>
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template< class Iter1, class Iter2 > typename reverse_iterator<Iter>::difference_type |
(until C++11) | |
template< class Iter1, class Iter2 > auto operator-( const reverse_iterator<Iter1>& lhs, |
(since C++11) (constexpr since C++17) |
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Returns the distance between two iterator adaptors.
Parameters
lhs, rhs | - | iterator adaptors to compute the difference of |
Return value
rhs.base() - lhs.base()
Notes
operator- returns rhs.base() - lhs.base() rather than lhs.base() - rhs.base() because this is a reverse iterator.
Example
Run this code
#include <iostream> #include <iterator> #include <list> #include <vector> int main() { std::vector vec{0, 1, 2, 3}; std::reverse_iterator<std::vector<int>::iterator> vec_ri1{std::reverse_iterator{vec.rbegin()}}, vec_ri2{std::reverse_iterator{vec.rend()}}; std::cout << (vec_ri2 - vec_ri1) << ' '; // 4 std::cout << (vec_ri1 - vec_ri2) << '\n'; // -4 std::list lst{5, 6, 7, 8}; std::reverse_iterator<std::list<int>::iterator> lst_ri1{std::reverse_iterator{lst.rbegin()}}, lst_ri2{std::reverse_iterator{lst.rend()}}; // auto n = (lst_ri1 - lst_ri2); // Error: the underlying iterators do not // model random access iterator }
Output:
4 -4
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
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LWG 280 | C++98 | heterogeneous subtraction was not allowed | allowed |
See also
advances or decrements the iterator (public member function) | |
advances the iterator (function template) |