std::chrono::year::year
From cppreference.com
year() = default; |
(1) | (since C++20) |
constexpr explicit year( int y ) noexcept; |
(2) | (since C++20) |
Constructs a year
object.
1) Default constructor leaves the year value uninitialized.
2) If y is in the range
[
-32767,
32767]
, constructs a year
object holding the year value y. Otherwise the value held is unspecified.Example
Run this code
#include <chrono> #include <iostream> int main() { using namespace std::chrono; constexpr int leap_years = [] { int count{}; for (int i{year::min()}; i <= int{year::max()}; ++i) if (year{i}.is_leap()) // uses constructor (2) ++count; return count; } (); static_assert(15891 == leap_years); std::cout << "There are " << leap_years << " leap years in the range [" << int(year::min()) << ", " << int(year::max()) << "].\n"; }
Output:
There are 15891 leap years in the range [-32767, 32767].