std::chrono::year::operator++, std::chrono::year::operator--
From cppreference.com
constexpr std::chrono::year& operator++() noexcept; |
(1) | (since C++20) |
constexpr std::chrono::year operator++( int ) noexcept; |
(2) | (since C++20) |
constexpr std::chrono::year& operator--() noexcept; |
(3) | (since C++20) |
constexpr std::chrono::year operator--( int ) noexcept; |
(4) | (since C++20) |
Adds or subtracts 1 from the year value.
1,2) Performs *this += std::chrono::years{1};.
3,4) Performs *this -= std::chrono::years{1};.
Parameters
(none)
Return value
1,3) A reference to this
year
after modification.2,4) A copy of the
year
made before modification.Notes
If the result would be outside the range [
-32767,
32767]
, the actual stored value is unspecified.
Example
Run this code
#include <chrono> #include <iostream> int main() { std::cout << std::boolalpha; std::chrono::year y{2020}; std::cout << (++y == std::chrono::year(2021)) << ' '; std::cout << (--y == std::chrono::year(2020)) << '\n'; using namespace std::literals::chrono_literals; y = 32767y; y++; //← unspecified, see ↑ Notes ↑ std::cout << static_cast<int>(y) << '\n'; }
Possible output:
true true -32768
See also
adds or subtracts a number of years from a year (public member function) | |
(C++20) |
performs arithmetic on year s (function) |