std::unique_ptr<T,Deleter>::get_deleter
From cppreference.com
< cpp | memory | unique ptr
Deleter& get_deleter() noexcept; |
(since C++11) (constexpr since C++23) |
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const Deleter& get_deleter() const noexcept; |
(since C++11) (constexpr since C++23) |
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Returns the deleter object which would be used for destruction of the managed object.
Parameters
(none)
Return value
The stored deleter object.
Example
Run this code
#include <iostream> #include <memory> struct Foo { Foo() { std::cout << "Foo() 0x" << std::hex << (void*)this << '\n'; } ~Foo() { std::cout << "~Foo() 0x" << std::hex << (void*)this << '\n'; } }; struct D { int number; void bar() { std::cout << "call D::bar(), my number is: " << std::dec << number << '\n'; } void operator()(Foo* p) const { std::cout << "call deleter for Foo object 0x" << std::hex << (void*)p << '\n'; delete p; } }; int main() { std::cout << "main start\n"; std::unique_ptr<Foo, D> up1(new Foo(), D(42)); D& del1 = up1.get_deleter(); del1.bar(); std::unique_ptr<Foo, D> up2(new Foo(), D(43)); D& del2 = up2.get_deleter(); auto* released = up2.release(); del2(released); std::cout << "main end\n"; }
Output:
main start Foo() 0x0x90cc30 call D::bar(), my number is: 42 Foo() 0x0x90cc50 call deleter for Foo object 0x0x90cc50 ~Foo() 0x0x90cc50 main end call deleter for Foo object 0x0x90cc30 ~Foo() 0x0x90cc30
See also
returns the deleter of specified type, if owned (function template) |