std::iscntrl(std::locale)
From cppreference.com
| Defined in header <locale>
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| template< class CharT > bool iscntrl( CharT ch, const locale& loc ); |
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Checks if the given character is classified as a control character by the given locale's std::ctype facet.
Parameters
| ch | - | character |
| loc | - | locale |
Return value
Returns true if the character is classified as a control character, false otherwise.
Possible implementation
template<class CharT> bool iscntrl(CharT ch, const std::locale& loc) { return std::use_facet<std::ctype<CharT>>(loc).is(std::ctype_base::cntrl, ch); } |
Example
Demonstrates the use of iscntrl() with different locales (OS-specific).
Run this code
#include <iostream> #include <locale> int main() { const wchar_t CCH = L'\u0094'; // Destructive Backspace in Unicode std::locale loc1("C"); std::cout << "iscntrl(CCH, C locale) returned " << std::boolalpha << std::iscntrl(CCH, loc1) << '\n'; std::locale loc2("en_US.UTF8"); std::cout << "iscntrl(CCH, Unicode locale) returned " << std::boolalpha << std::iscntrl(CCH, loc2) << '\n'; }
Possible output:
iscntrl(CCH, C locale) returned false iscntrl(CCH, Unicode locale) returned true
See also
| checks if a character is a control character (function) | |
| checks if a wide character is a control character (function) |