std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_weekday)
From cppreference.com
< cpp | chrono | year month weekday
constexpr std::chrono::year_month_weekday operator+( const std::chrono::year_month_weekday& ymwd, |
(1) | (since C++20) |
constexpr std::chrono::year_month_weekday operator+( const std::chrono::months& dm, |
(2) | (since C++20) |
constexpr std::chrono::year_month_weekday operator+( const std::chrono::year_month_weekday& ymwd, |
(3) | (since C++20) |
constexpr std::chrono::year_month_weekday operator+( const std::chrono::years& dy, |
(4) | (since C++20) |
constexpr std::chrono::year_month_weekday operator-( const std::chrono::year_month_weekday& ymwd, |
(5) | (since C++20) |
constexpr std::chrono::year_month_weekday operator-( const std::chrono::year_month_weekday& ymwd, |
(6) | (since C++20) |
1,2) Adds dm.count() months to the date represented by ymwd. The result has the same
year()
and month()
as std::chrono::year_month(ymwd.year(), ymwd.month()) + dm and the same weekday()
and index()
as ymwd.3,4) Adds dy.count() years to the date represented by ymwd. The result is equivalent to std::chrono::year_month_weekday(ymwd.year() + dy, ymwd.month(), ymwd.weekday_indexed()).
5) Subtracts dm.count() months from the date represented by ymwd. Equivalent to ymwd + -dm.
6) Subtracts dy.count() years from the date represented by ymwd. Equivalent to ymwd + -dy.
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (3,4,6) are preferred if the call would otherwise be ambiguous.
Notes
Even if ymwd.ok() is true, the resulting year_month_weekday
may not represent a valid date if ymwd.index() is 5.
Example
Run this code
#include <cassert> #include <chrono> #include <iostream> int main() { auto ymwdi{1/std::chrono::Wednesday[1]/2021}; std::cout << ymwdi << '\n'; ymwdi = std::chrono::years(5) + ymwdi; // First Wednesday in January, 2026 std::cout << ymwdi << '\n'; assert(static_cast<std::chrono::year_month_day>(ymwdi) == std::chrono::January/7/2026); ymwdi = ymwdi - std::chrono::months(6); // First Wednesday in July, 2025 std::cout << ymwdi << '\n'; assert(static_cast<std::chrono::year_month_day>(ymwdi) == std::chrono::July/2/2025); }
Output:
2021/Jan/Wed[1] 2026/Jan/Wed[1] 2025/Jul/Wed[1]