std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_day)
Defined in header <chrono>
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constexpr std::chrono::year_month_day operator+( const std::chrono::year_month_day& ymd, const std::chrono::months& dm |
(since C++20) | |
constexpr std::chrono::year_month_day operator+( const std::chrono::months& dm, const std::chrono::year_month_day& ymd |
(since C++20) | |
constexpr std::chrono::year_month_day operator+( const std::chrono::year_month_day& ymd, const std::chrono::years& dy |
(since C++20) | |
constexpr std::chrono::year_month_day operator+( const std::chrono::years& dy, const std::chrono::year_month_day& ymd |
(since C++20) | |
constexpr std::chrono::year_month_day operator-( const std::chrono::year_month_day& ymd, const std::chrono::months& dm |
(since C++20) | |
constexpr std::chrono::year_month_day operator-( const std::chrono::year_month_day& ymd, const std::chrono::years& dy |
(since C++20) | |
For durations that are convertible to both std::chrono::years and std::chrono::months, the years
overloads (3,4,6) are preferred if the call would otherwise be ambiguous.
Notes
Even if ymd.ok() is true, the resulting year_month_day
may not represent a valid date if ymd.day() is 29, 30, or 31.
Example
#include <chrono> #include <iostream> int main() { std::cout << std::boolalpha; auto ymd{std::chrono::day(1)/std::chrono::July/2021}; ymd = ymd + std::chrono::months(4); std::cout << (ymd.month() == std::chrono::November) << ' ' << (ymd.year() == std::chrono::year(2021)) << ' '; ymd = ymd - std::chrono::years(10); std::cout << (ymd.month() == std::chrono::month(11)) << ' ' << (ymd.year() == std::chrono::year(2011)) << '\n'; }
Output:
true true true true