std::variant<Types...>::visit
From cppreference.com
template< class Self, class Visitor > constexpr decltype(auto) visit( this Self&& self, Visitor&& vis ); |
(1) | (since C++26) |
template< class R, class Self, class Visitor > constexpr R visit( this Self&& self, Visitor&& vis ); |
(2) | (since C++26) |
Applies the visitor vis (a Callable that can be called with any combination of types from the variant) to the variant held by self.
Given type V as decltype(std::forward_like<Self>(std::declval<variant>())), the equivalent call is:
1) return std::visit(std::forward<Visitor>(vis), (V) self);.
2) return std::visit<R>(std::forward<Visitor>(vis), (V) self);.
Parameters
vis | - | a Callable that accepts every possible alternative from the variant |
self | - | variant to pass to the visitor |
Return value
1) The result of the std::visit invocation.
2) Nothing if
R
is (possibly cv-qualified) void; otherwise the result of the std::visit<R> invocation.Exceptions
Only throws if the call to std::visit throws.
Notes
Feature-test macro | Value | Std | Feature |
---|---|---|---|
__cpp_lib_variant |
202306L | (C++26) | member visit
|
Example
Run this code
#include <iostream> #include <string> #include <variant> // helper type for the visitor template<class... Ts> struct overloads : Ts... { using Ts::operator()...; }; int main() { std::variant<int, std::string> var1{42}, var2{"abc"}; auto use_int = [](int i){ std::cout << "int = " << i << '\n'; }; auto use_str = [](std::string s){ std::cout << "string = " << s << '\n'; }; #if (__cpp_lib_variant >= 202306L) var1.visit(overloads{use_int, use_str}); var2.visit(overloads{use_int, use_str}); #else std::visit(overloads{use_int, use_str}, var1); std::visit(overloads{use_int, use_str}, var2); #endif }
Output:
int = 42 string = abc