std::identity
From cppreference.com
< cpp | utility | functional
Defined in header <functional>
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struct identity; |
(since C++20) | |
std::identity
is a function object type whose operator() returns its argument unchanged.
Member types
Type | Definition |
is_transparent
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unspecified |
Member functions
operator() |
returns the argument unchanged (public member function) |
std::identity::operator()
template< class T > constexpr T&& operator()( T&& t ) const noexcept; |
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Returns std::forward<T>(t).
Parameters
t | - | argument to return |
Return value
std::forward<T>(t).
Notes
std::identity
serves as the default projection in constrained algorithms. Its direct usage is usually not needed.
Example
Run this code
#include <algorithm> #include <functional> #include <iostream> #include <ranges> #include <string> struct Pair { int n; std::string s; friend std::ostream& operator<<(std::ostream& os, const Pair& p) { return os << '{' << p.n << ", " << p.s << '}'; } }; // A range-printer that can print projected (modified) elements of a range. template<std::ranges::input_range R, typename Projection = std::identity> //<- Notice the default projection void print(std::string_view const rem, R&& range, Projection projection = {}) { std::cout << rem << '{'; std::ranges::for_each( range, [O = 0](const auto& o) mutable { std::cout << (O++ ? ", " : "") << o; }, projection ); std::cout << "}\n"; } int main() { const auto v = {Pair{1, "one"}, {2, "two"}, {3, "three"}}; print("Print using std::identity as a projection: ", v); print("Project the Pair::n: ", v, &Pair::n); print("Project the Pair::s: ", v, &Pair::s); print("Print using custom closure as a projection: ", v, [](Pair const& p) { return std::to_string(p.n) + ':' + p.s; }); }
Output:
Print using std::identity as a projection: {{1, one}, {2, two}, {3, three}} Project the Pair::n: {1, 2, 3} Project the Pair::s: {one, two, three} Print using custom closure as a projection: {1:one, 2:two, 3:three}
See also
(C++20) |
returns the type argument unchanged (class template) |