std::wmemcpy
From cppreference.com
Defined in header <cwchar>
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wchar_t* wmemcpy( wchar_t* dest, const wchar_t* src, std::size_t count ); |
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Copies exactly count successive wide characters from the wide character array pointed to by src to the wide character array pointed to by dest. If the objects overlap, the behavior is undefined. If count is zero, the function does nothing.
Parameters
dest | - | pointer to the wide character array to copy to |
src | - | pointer to the wide character array to copy from |
count | - | number of wide characters to copy |
Return value
dest
Notes
This function's analog for byte strings is std::strncpy, not std::strcpy.
This function is not locale-sensitive and pays no attention to the values of the wchar_t objects it copies: nulls as well as invalid characters are copied too.
Example
Run this code
#include <clocale> #include <cwchar> #include <iostream> #include <iterator> #include <locale> int main(void) { const wchar_t from1[] = L"नमस्ते"; const wchar_t from2[] = L"Բարև"; const std::size_t sz1 = std::size(from1); const std::size_t sz2 = std::size(from2); wchar_t to[sz1 + sz2]; std::wmemcpy(to, from1, sz1); // copy from1, along with its null terminator std::wmemcpy(to + sz1, from2, sz2); // append from2, along with its null terminator std::setlocale(LC_ALL, "en_US.utf8"); std::wcout.imbue(std::locale("en_US.utf8")); std::wcout << L"Wide array contains: "; for (std::size_t n = 0; n < std::size(to); ++n) if (to[n]) std::wcout << to[n]; else std::wcout << L"\\0"; std::wcout << L'\n'; }
Possible output:
Wide array contains: नमस्ते\0Բարև\0
See also
copies a certain amount of characters from one string to another (function) | |
copies a certain amount of wide characters between two, possibly overlapping, arrays (function) | |
C documentation for wmemcpy
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